Simple Y-parameter (admittance-parameter) matrix problem?

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The discussion revolves around solving a Y-parameter (admittance-parameter) matrix problem, focusing on the general form of the equations. The user clarifies that the input current I1 can be expressed as I1 = Y11(V1) + Y12(V2) and attempts to calculate Y11 using a 1V source and short-circuiting the output. The calculation leads to Y11 being expressed as Y11 = (1/Ya + 1/Yb)s. The key takeaway is that for two networks, the input and output currents are additive, which also applies to their corresponding admittance parameters. The conclusion is that the first choice (A) is identified as the correct answer.
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simple Y-parameter (admittance-parameter) matrix problem??

Homework Statement


vdctiv.png



Homework Equations


general form of Y-parameter is
[I1]=[Y11 Y12][V1]
[I2]=[Y21 Y22][V2]

The Attempt at a Solution


i think i was confused what exactly this problem asked for. the general equation for I1 for instance you would add the variables, so I1=Y11(V1)+Y12(V2). to calculate Y11 also, you would add a 1V source on the left side, and short-circuit the right side. so I'm pretty sure it would be Y11=(\frac{1}{Ya}+\frac{1}{Yb})s. since the only signs i saw in these equations were '+' i put the 1st choice (A) as my answer.
 
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A is the answer.

The idea is that, for two networks, the input currents i1A and i11B are added and so are the output currents i2A and i2B . This implies that the individual admittance parameters yij for A and B are also added.
 

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