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Simultaneous Eigenkets?

  1. Feb 12, 2015 #1
    1. The problem statement, all variables and given/known data
    If A and B are observables, suppose that the simultaneous eigenkets of A and B, {|a',b'>} form a complete orthonormal set of base kets.
    Can we always conclude that [A,B]=0

    2. Relevant equations
    A|a'> = a' |a'>
    B|b'> = b' |b'>

    3. The attempt at a solution
    I Honestly don't know where to start.
    What does it mean that the are "Simultaneous Eigenkets"?

    I do know that it implies that you can take a measurement of both without having to destroy the previous measurement. Everywhere i look seems to start at the opposite end assuming that they commute.
    So if someone can explain what "Simultaneous eigenkets" means, I can probably get a bunch further..
    I want to figure this out but i can't seem to really even get started.
     
  2. jcsd
  3. Feb 12, 2015 #2

    ShayanJ

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    Gold Member

    It means that you can write ## A|a',b'\rangle=a' |a',b'\rangle ## and ## B|a',b'\rangle=b'|a',b'\rangle ##, which means ##|a',b'\rangle## is the eigenket of both A and B, so their "simultaneous eigenket"!
     
  4. Feb 12, 2015 #3

    Dick

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    Science Advisor
    Homework Helper

    |a',b'> is a simultaneous eigenket of both A and B if it's an eigenket of BOTH the operators A and B. I.e. A|a',b'>=a'|a',b'> and B|a',b'>=b'|a',b'>. Think about what the matrix and A and B look like in that basis.
     
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