Single bead on a vertical circle.

AI Thread Summary
A bead with a hole is placed in a frictionless vertical circle that spins around its vertical axis, starting at the bottom. The discussion centers on the bead's behavior at high angular velocities. While one viewpoint suggests that the bead could rise along the circle's shape, another argues that it would remain at the bottom in an ideal scenario without perturbations. However, in reality, any slight disturbance would cause the bead to shift, with its height influenced by the angular velocity. The analogy of a ball on a pyramid illustrates the concept of dynamic equilibrium, where the bead would likely roll down if disturbed.
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Imagine that a single bead has a hole in it. It is passed inside a " vertical " circle with no friction. Imagine that the "vertical"circle moves by spinning around its vertical axis and that the bead is, AT THE BEGINNING, on the bottom of the vertical circle.

We had another problem related to this. However, I am wondering what would happen to the bead if the angular velocity of the vertical circle was very very high.

My teacher says that the bead could higher following the shape of the vertical circle.

However, I think that, as long as there is no perturbation, the ball will stay at the bottom. Is this correct?

I am just starting to get a grasp of Newtonian laws.
 
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Yes, I don't think the bead would move, but that would be a very ideal case. Realistically, it would be shifted one way or another, and then its height determined by the angular velocity of the ring.

Think of a ball at the top of a pyramid. It's in "dynamic equilibrium," where it will technically stay in the same place, but realistically roll down one of the sides.
 
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