Sinusoidial waves: Frequency is not dependant on speed?

AI Thread Summary
The discussion centers on the confusion regarding the relationship between wave speed, frequency, and wavelength in sinusoidal waves. The initial equation v = λf suggests that speed is dependent on frequency, leading to a misunderstanding when comparing two waves of different frequencies. It is clarified that the wave speed on a stretched string is determined by tension and mass density, not frequency alone. When frequency increases, the wavelength decreases, keeping the wave speed constant. The correct formula for wave speed on a string is v = √(T/μ), resolving the confusion.
Willjeezy
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Homework Statement



I am really confused.

v = λ f

doesn't that imply that speed is dependent on frequency?

There is a question in my book that says:

A sinusoidal wave of frequency f is traveling along a stretched string. The string is brought to rest, and a second traveling wave of frequency 2f is established on the string.
(i) what is the wave speed of the second wave?


Homework Equations



v = λ f

The Attempt at a Solution



so I figured the answer would be something like:

since v1=λf
it follows that, if the second wave has frequency 2f
v2 = λ(2f)
v2 = 2 (λf)
v2 = 2 (v1)

but somehow the answer is: "the same as the first wave" Can someone explain this to me?
 
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Willjeezy said:

Homework Statement



I am really confused.

v = λ f

doesn't that imply that speed is dependent on frequency?

There is a question in my book that says:

A sinusoidal wave of frequency f is traveling along a stretched string. The string is brought to rest, and a second traveling wave of frequency 2f is established on the string.
(i) what is the wave speed of the second wave?


Homework Equations



v = λ f

The Attempt at a Solution



so I figured the answer would be something like:

since v1=λf
it follows that, if the second wave has frequency 2f
v2 = λ(2f)
v2 = 2 (λf)
v2 = 2 (v1)

but somehow the answer is: "the same as the first wave" Can someone explain this to me?

You are assuming λ doesn't change. You have the wrong equation. What equation determines the speed of a wave on a stretched string? Might just involve tension and mass density, yes?
 
Ohhhhh, right right. If frequency increases λ would get shorter.

i flipped two pages down and found:
v=√(T/μ)

problem solved. Thanks.
 
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