Sketch graphs showing vertical & horizontal asymptotes and relative extrema

Glissando
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Homework Statement


Sketch the graphs of the following function showing vertical and horizontal asymptotes and relative extrema:

f(x) = (x2-1)/(x2-4)


Homework Equations


Limits, zeroes, derivatives


The Attempt at a Solution


I know that I have the majority of the answers right, the only problem I'm having is with part of the vertical asymptote.

VA = positive and negative 2

The problem is with -2:

lim (-22-1)/(-2+)2-4)
x->-2+

= (4-1)/(4+-4) = +infinity

lim ((-2)2-1)/((-2-)2-4)
x->-2-

= (4-1)/(4--4) = negative infinity

But my graphing calculator shows the exact opposite ):!

Any help is appreciated! Thank you <3
 
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The limit as x->(-2)+ is +infinity. The limit as x->(-2)- is -infinity. I'm not sure what your graphing calculator's problem is.
 
Dick said:
The limit as x->(-2)+ is +infinity. The limit as x->(-2)- is -infinity. I'm not sure what your graphing calculator's problem is.

...I guess I'm sketching the graph wrong then...Thank you for your help (:!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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