Sketching Signal x(t): 2^(-t*u(t))

  • Thread starter Thread starter drkidd22
  • Start date Start date
  • Tags Tags
    Signal
AI Thread Summary
The signal x(t) = 2^(-t*u(t)) is defined as a piecewise function, where x(t) equals 1 for t < 0 and 2^(-t) for t > 0. The square of the signal, x(t)^2, also follows a piecewise definition: it is 1 for t < 0 and 2^(-2t) for t > 0. When integrating x(t)^2 from -1 to 1, the integral splits into two parts: from -1 to 0, the integral is 1, and from 0 to 1, it is the integral of 2^(-2t). The discussion focuses on verifying the correctness of the calculations and the approach taken for sketching the signal. The analysis emphasizes the importance of understanding piecewise functions in signal processing.
drkidd22
Messages
59
Reaction score
0

Homework Statement



Sketch the signal:
x(t) = 2^(-t*u(t)) over (-1 < t < 1)

The Attempt at a Solution


Attached is an excel fine with my work out. I want to know is it is correct.
 

Attachments

Physics news on Phys.org
It is simplest to think of this as a piecewise function
x(t) = \begin{cases}<br /> 1, t &lt; 0 \\<br /> 2^{-t}, t&gt;0<br /> \end{cases}
then
x(t)^2 = \begin{cases}<br /> 1, t &lt; 0 \\<br /> 2^{-2t}, t&gt;0<br /> \end{cases}
so when you integrate x(t)^2 from -1 to 1, it breaks apart into two integrals. One is from -1 to 0 of 1, and the other is from 0 to 1 of 2^{-2t}.
 

Similar threads

Replies
4
Views
2K
Replies
7
Views
2K
Replies
4
Views
1K
Replies
1
Views
2K
Replies
7
Views
2K
Replies
2
Views
2K
Replies
6
Views
5K
Replies
4
Views
2K
Back
Top