The block of glass n = 1.5 shown in cross section in the figure (Intro 1 figure) is surrounded by air. A ray of light enters the block at its left-hand face with incident angle Θ1 and reemerges into the air from the right-hand face directed parallel to the block's base.
n1 sin Θ1 = n2 sin Θ2 = n1 sin Θ3
The Attempt at a Solution
3. n1 sin Θ1 =n2 sin Θ2 = n1 sin Θ3
n1 =1, n2=1.5, Θ3=45
1 sin 45 = 1.5 sin(x) x= 28.125
1.5 sin 28.125 = 1 sin(x) x = 45