1. The problem statement, all variables and given/known data You want to construct a solenoid 20cm long that has an interior magnetic field Strength B (Bc) of about 1.5MN/C. The coil has to be wound as a single layer of wire around a form whose diameter is 3.0 cm. You have two spools of wire handy. #18 wire has a diameter of about 1.02mm and can carry a current of 6.0A before overheating. #26 wire has a diameter of 0.41mm and can carry up to 1.0A. Which kind of wire should you use and why? What potential difference do you want to put across the coil's end? 2. Relevant equations B=NI/(cLE0)...or simplified as about 377NI/L. 3. The attempt at a solution 377NI/L must equal about 1.5X10^6N/C.......so NI/L must equal 3979. I Have an I....and don't really know where to go from here...and not even sure if this is the right path to take. Not really understanding the question? So I unwind the wires and see how many of them I'd need to fill the 3cm diameter? Any help would be appreciated.