Solution: Distance Traveled by Car with Air Resistance

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The discussion focuses on calculating the distance a car travels after running out of fuel, factoring in air resistance. The retarding force is defined differently based on the car's speed, using two equations: \mu u^2 for speeds above a critical speed and \lambda u for speeds below it. Newton's second law is applied to relate acceleration to the retarding force, with the goal of finding the distance traveled. The solution involves using energy principles, integrating the forces over distance, and evaluating the resulting integrals. The discussion emphasizes the importance of correctly applying these concepts to derive the distance traveled without fuel.
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Any got any ideas of how to go around this question? Thanks

A car of mass m is moving along a horizontal track with speed U>uc when it runs out of fuel. The retarding force due to air resistance is equal to
(i) \mu u^2 for speed u>uc
and (ii) \lambda u for speed u<uc

By writing Newton's second law in the form

ma = mu du/dx = retarding force
where x is distance travelled.

Find the distance traveled without fuel
 
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Jess1986 said:
Any got any ideas of how to go around this question? Thanks

A car of mass m is moving along a horizontal track with speed U>uc when it runs out of fuel. The retarding force due to air resistance is equal to
(i) \mu u^2 for speed u>uc
and (ii) \lambda u for speed u<uc

By writing Newton's second law in the form

ma = mu du/dx = retarding force
where x is distance travelled.

Find the distance traveled without fuel

Use energy. The car stops when its energy runs out.

\int_{u}^{0} Fdx = m\int_{u}^{0} udu = m\int_{u}^{u_c} udu + m\int_{u_c}^{0} udu

By inserting the expressions for u evaluate the two integrals.

AM
 
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