1. The problem statement, all variables and given/known data A solution of copper 2 sulphate is prepared by placing 5.80g of copper 2 sulphate in a flask and adding enough water to prepare 125 ml of solution. When a 25.0ml sample of this solution is added to 125ml of 0.125 mol/L sodium hydroxide a precipitate forms. Calculate the mass of the precipitate formed in the reaction. 2. Relevant equations n=cv m=nM 3. The attempt at a solution The percipitate i found would be cu(OH)2 which would have the same mole as NaOH (n=cv) and then u would use the formula m=nM to find mass. The answer i got is 0.762g but i didnt use any info about the copper 2 sulphate, is this right?