Solve Constrained Motion: Aa, Ab, Ac, Ad

  • Thread starter Thread starter makeez
  • Start date Start date
  • Tags Tags
    Motion
AI Thread Summary
The discussion revolves around solving a constrained motion problem from an exam paper, focusing on the tensions in the strings. The user has calculated the accelerations as Aa = -10 m/s², Ad = -5 m/s², Ac = 20 m/s², and Ab = 0 m/s², and seeks confirmation of these values and guidance for part c, which involves calculating the tensions. The approach taken includes setting up equations based on the constraints of the system. The suggestion to apply Newton's second law for mass C to find the net force and subsequently the tensions is highlighted as a key step. Understanding the relationships between the accelerations and applying the correct physical laws will lead to the solution for part c.
makeez
Messages
3
Reaction score
0
http://img101.photolava.com/2009/10/21/engr-vswpt7nk.jpg
An old exam paper practice question. I can get up to b) but i am having trouble with the tensions.

I got for Aa=-10mms-2 Ad=-5mms-2, while Ac is given to be 20mms-2 and Ab=0mms-2.
Is this corrent and if so how do I go about solving question c?

This was done by creating the constraints.
2Aa + 2Ab + Ac = 0
2Ad - Aa - Ab = 0
 
Last edited by a moderator:
Physics news on Phys.org
Welcome to PF!

Hi makeez! Welcome to PF! :smile:

(question c is the tension in the strings)

Start with good ol' Newton's second law for mass C … Fnet = ma :wink:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top