Solve Energy Dissipation in Resistor: I = 0.09 A, R = 80.0 Ω

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To calculate the total energy dissipated as heat in a resistor with a resistance of 80.0 Ω and a current of 0.09 A over one minute, the power can be determined using the formula P = I²R. Substituting the values, the power is calculated as P = (0.09 A)² * (80.0 Ω), resulting in a power dissipation. To find the total energy, the relationship P = U/t can be rearranged to U = P * t, where t is the time in seconds. By converting one minute to seconds and multiplying by the power, the total energy dissipated can be calculated. This approach effectively utilizes the power formula to determine energy dissipation in resistors.
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Homework Statement



What is the total energy dissipated as heat in a resistor of resistance R = 80.0 Ω when a current of I = 0.09 A passes through it for 1 minute?

Homework Equations




The Attempt at a Solution



From the given values I can work out the potential difference, but I'm stuck here because I don't know what formula to use with energy in it. But I know that electric power can be found from P=IV=I2R, but I don't know how this helps to find energy. Of course I know that P=\frac{dU}{dt}, but I don't see how to solve for the energy... :confused:
 
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It seems you have the answer hiding right in front of you...

If you know that the power drop across a resistor is (I^2)(R) then you can calculate that given the values.

Next if you assume that it drops all that power through heat 'U' over that 1min and you know that P=U/t then...
 

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