Solve for nGeometric Sequences: Solving for Number of Terms

AI Thread Summary
To find the number of terms in the geometric sequence 2, 10, 50, ..., 1250, the equation 1250 = 2 * 5^(n-1) is used. By isolating 5^(n-1) and simplifying, it becomes clear that 5^(n-1) = 625. Recognizing that 625 can be expressed as 5^4 leads to the conclusion that n-1 must equal 4. Therefore, solving for n gives the final result of n = 5, indicating there are five terms in the sequence.
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Homework Statement



Hi, I was trying to work out this question, but i kinda got stuck. Can anyone help me please?
Thanks

4. Find the number of terms in each of these geometric sequences.

2,10,50...1250


Homework Equations



ar^n-1


The Attempt at a Solution



1250=2x5^n-1
 
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I take it you mean 1250=2*5^{n-1} with n starting at 1? You're on the right track. What is the problem with the expression you found so far? You are unable to solve it for n? Hint: logarithm
 
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i don't get what the next step is
 
What does n represent in that formula?
 
n is the term, but i don't know how to find it
 
"The term", you mean is the number of terms in the sequence. The first step in solving it is to put 5^(n-1) on one side and the other terms on the other side. Then take the logarithm on both sides.
 
so do i have to balance both sides and eliminate 1250?
 
An equation is balanced by definition. If you substitute x=5^(n-1) then the equation becomes 1250=2x. Now solve this equation for x and then back substitute x.

ps. Are you familiar with logarithms?
 
Thank you very much. I've just started learning about it, so I'm trying to get the hang of it, but thank you for helping me.
 
  • #10
You're welcome, but have you found the solution?
 
  • #11
1250= 2x so x=1250/2 x=625

oh no, I'm getting confused again. sorry
 
  • #12
Correct x=625 and because we substituted x=5^(n-1) we know that 5^(n-1)=625. We now want to write 625 in terms of 5 raised to a certain exponent. For example we can write 8=2^3, 125=5^3. Try to write 625 in a similar way.
 
  • #13
so it can be 625=25^2
 
  • #14
Yes that is correct although not entirely what I had in mind. Note that you can write 25=5^2 therefore 25^2=(5^2)^2=5^4=625.

So now your equation becomes:

<br /> 5^{n-1}=5^4<br />

Therefore n-1 equals...?
 
  • #15
n-1= 5
 
  • #16
No the two exponents need to be equal to each other, it is the only way the equation can hold. So I will ask you again n-1=?

What you're saying now is that 5^5=5^4. Convince yourself that this cannot be correct.
 
  • #17
ohhhh n-1= 5-1?
 
  • #18
Why do you think so, explain your reasoning behind it.
 
  • #19
because 5^(5-1) which equals to 5^4
 
  • #20
Well your reasoning and your answer are correct although a bit of a detour. You know that both exponents need to be the same therefore n-1=4.
 
  • #21
ohhhhh, i see now. Thank you
 
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