- #1
apples
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I am stuck with 2 questions.
1. http://132.239.150.164/math/img/math_967.5_fabcf8ac5b3f2459050993af33426844.png[/URL]
2. http://132.239.150.164/math/img/math_972_41ec111060693034ac0775fd52778392.png[/URL]
http://132.239.150.164/math/img/math_989.5_89c6805f9e6a047e24c9d1b535209efd.png
1.
I take u= (4-x)^(1/2)
dv = xdx
du = 1/2* (4-x)^(-1/2)
v= (x^2)/2
I get stuck at
((x^2)/2)*(4-x)^(1/2)- ∫[(x^2)dx/4*(4-x)^(1/2)2. I take u= (arcsin x)^2 dv=dx or 1
du= (2arcsin x)/((1-x^2)^(1/2)]
v=x
so
x(arcsin x)^2 -2 ∫[(x arcsin x dx)/(1-x^2)^(1/2)]
I don't know what to do after that.
How do I solve the red.
1. http://132.239.150.164/math/img/math_967.5_fabcf8ac5b3f2459050993af33426844.png[/URL]
2. http://132.239.150.164/math/img/math_972_41ec111060693034ac0775fd52778392.png[/URL]
Homework Equations
http://132.239.150.164/math/img/math_989.5_89c6805f9e6a047e24c9d1b535209efd.png
The Attempt at a Solution
1.
I take u= (4-x)^(1/2)
dv = xdx
du = 1/2* (4-x)^(-1/2)
v= (x^2)/2
I get stuck at
((x^2)/2)*(4-x)^(1/2)- ∫[(x^2)dx/4*(4-x)^(1/2)2. I take u= (arcsin x)^2 dv=dx or 1
du= (2arcsin x)/((1-x^2)^(1/2)]
v=x
so
x(arcsin x)^2 -2 ∫[(x arcsin x dx)/(1-x^2)^(1/2)]
I don't know what to do after that.
How do I solve the red.
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