Solve Internal Resistance Homework Problem

AI Thread Summary
The problem involves a 6.0V battery connected to a parallel combination of a 10 ohm and a 40 ohm resistor, resulting in a total current of 0.25A. The combined resistance of the resistors is calculated to be 8 ohms. Using the equation E = IR + Ir, it is determined that the total resistance (R + r) must equal 24 ohms. While one calculation suggests the internal resistance is 16 ohms, the correct internal resistance is identified as 4 ohms according to the answer book. The discussion highlights the importance of correctly applying the formula to find the internal resistance.
nokia8650
Messages
216
Reaction score
0

Homework Statement



"A 6.0V battery is connected across a parallel combination of two resistors ; one 10 ohm and one 40 ohm. Thee total current provided by the battery is 0.25A. Obtain a value for the internal resistance.


Homework Equations



E= IR +Ir

The Attempt at a Solution



I find the combined resistance of the resistors to be 8 ohms, and sub this into the equation above, and solve for little r, but get an answer of 16 ohms; the correct answer, according to the answer book is 4 ohms. Please can you show me a correct solution to the question!

Thanks
 
Physics news on Phys.org
Your answer is correct. Since 6.0 V produces 0.25 A of current, R+r must be 24 ohms.
10 and 40 ohms parallel is indeed 8 ohms, so r must be 16 ohms.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top