Solve Jumping Toy Problem: Find Spring Constant & Power

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AI Thread Summary
To solve the jumping toy problem, the spring constant can be calculated using conservation of energy, applying the formula 1/2kx² = mgh. The initial attempt to find the spring constant using the formula k = F/Δx was incorrect due to miscalculating the force. For average power, the work done by the spring can be determined using the work-energy principle, and the time can be derived from the period of oscillation. Instantaneous power can be calculated at different compression levels by adjusting the spring force accordingly. The approach using energy conservation and correct formulas is essential for accurate results.
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Homework Statement


A spring is compressed 1.5 cm and propels a 49g toy to a height of 45 cm.
a. Find the spring constant
b. The average power of the spring during propulsion.
c. The instantaneous power exerted when the compression is just .75cm

Homework Equations


k=F/\Deltax
Power=Work/time


The Attempt at a Solution


i thought the spring constant ,k, would be (mass of toy x 9.81)/(.015), but this is wrong.
then work would be, force(which i don't know how to find) x distance(.45).. but I am not sure
 
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Okay, but I'm still not sure how to find the spring constant, was I on the right track by using F/\Deltax, where x=.015 m
 
and force is equal to .049x9.81
 
Okay so i figured out the constant by conservation of energy.
1/2kx2=mgh, solve for k
then for power p=w/t, i find t by finding\omega=sqrt. (k/m) then using that to find T, the period.
then work= 1/2kx2, so then i just divide the w/T, would this be correct?
 
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