Solve Kinematics Homework on Spring:Q1,Q2

  • Thread starter Thread starter nahanksh
  • Start date Start date
  • Tags Tags
    Kinematics Spring
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
nahanksh
Messages
38
Reaction score
0

Homework Statement


http://online.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys211/oldexams/exam2/fa09/fig8.gif

A small block having a mass of 2 kg is in contact with an ideal spring of relaxed length 1 m and spring constant k = 100 N/m . The spring is compressed to a length of 0.5 m. The block is released from rest at x = 0.5 m. At x = 1 m the mass leaves the spring and comes to rest at x = 2 m. Throughout its entire motion the block slides on a rough surface with a coefficient of kinetic friction μk .

Q1) The maximum acceleration of the block occurs the instant the block begins to move.
True/FalseQ2) What is the coefficient of kinetic friction of the surface?

Homework Equations


The Attempt at a Solution



For the first question, i thought the acceleration is at maximum when the spring is about to move(at x=0.5m)... 'cause i thought the friction force will be exerted after this point reducing the acceleration...
What's wrong in my thought?

And, for the second question, i tried to get the velocity when x=1m using energy-conservation theorem, and i got m*v^2 = k*x^2 and hence v = 3.53

Now i used the constant acceleration formula, the final velocity is zero, and initial v = 3.53,
a= μmg/2 and the displacement = 1.

But then i got the answer as 0.62 which is wrong...

What's wrong in here?Please help me out with those two questions...
 
Last edited by a moderator:
Physics news on Phys.org
nahanksh said:
For the first question, i thought the acceleration is at maximum when the spring is about to move(at x=0.5m)... 'cause i thought the friction force will be exerted after this point reducing the acceleration...
What's wrong in my thought?
The spring still exerts a force on the block during the 0.5m to 1m period and thus continues to supply it with energy.
nahanksh said:
And, for the second question, i tried to get the velocity when x=1m using energy-conservation theorem, and i got m*v^2 = k*x^2 and hence v = 3.53

Now i used the constant acceleration formula, the final velocity is zero, and initial v = 3.53,
a= μmg/2 and the displacement = 1.

But then i got the answer as 0.62 which is wrong...

What's wrong in here?
Your energy conservation equation is wrong because it fails to account for energy loss due to friction during the initial period.
 
Spring energy = Kinetic energy of uncompressed spring + change in thermal energy