Solve Kinematics Homework on Spring:Q1,Q2

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SUMMARY

The discussion focuses on solving kinematics homework involving a 2 kg block interacting with an ideal spring (spring constant k = 100 N/m) and a rough surface with kinetic friction. The first question addresses the maximum acceleration of the block, which occurs when the spring is fully compressed at x = 0.5 m, contrary to the initial assumption that it happens just as the block begins to move. The second question involves calculating the coefficient of kinetic friction, where the user incorrectly applied the energy conservation theorem without accounting for energy loss due to friction, leading to an erroneous result of 0.62.

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  • Understanding of Newton's laws of motion
  • Familiarity with Hooke's Law and spring mechanics
  • Knowledge of energy conservation principles in physics
  • Basic concepts of friction and its effects on motion
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Homework Statement


http://online.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys211/oldexams/exam2/fa09/fig8.gif

A small block having a mass of 2 kg is in contact with an ideal spring of relaxed length 1 m and spring constant k = 100 N/m . The spring is compressed to a length of 0.5 m. The block is released from rest at x = 0.5 m. At x = 1 m the mass leaves the spring and comes to rest at x = 2 m. Throughout its entire motion the block slides on a rough surface with a coefficient of kinetic friction μk .

Q1) The maximum acceleration of the block occurs the instant the block begins to move.
True/FalseQ2) What is the coefficient of kinetic friction of the surface?

Homework Equations


The Attempt at a Solution



For the first question, i thought the acceleration is at maximum when the spring is about to move(at x=0.5m)... 'cause i thought the friction force will be exerted after this point reducing the acceleration...
What's wrong in my thought?

And, for the second question, i tried to get the velocity when x=1m using energy-conservation theorem, and i got m*v^2 = k*x^2 and hence v = 3.53

Now i used the constant acceleration formula, the final velocity is zero, and initial v = 3.53,
a= μmg/2 and the displacement = 1.

But then i got the answer as 0.62 which is wrong...

What's wrong in here?Please help me out with those two questions...
 
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nahanksh said:
For the first question, i thought the acceleration is at maximum when the spring is about to move(at x=0.5m)... 'cause i thought the friction force will be exerted after this point reducing the acceleration...
What's wrong in my thought?
The spring still exerts a force on the block during the 0.5m to 1m period and thus continues to supply it with energy.
nahanksh said:
And, for the second question, i tried to get the velocity when x=1m using energy-conservation theorem, and i got m*v^2 = k*x^2 and hence v = 3.53

Now i used the constant acceleration formula, the final velocity is zero, and initial v = 3.53,
a= μmg/2 and the displacement = 1.

But then i got the answer as 0.62 which is wrong...

What's wrong in here?
Your energy conservation equation is wrong because it fails to account for energy loss due to friction during the initial period.
 
Spring energy = Kinetic energy of uncompressed spring + change in thermal energy
 

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