Solve Kinetics, Springs: Find Collar Velocity at s=1 ft

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To determine the collar's velocity at s = 1 ft, the spring force must be calculated using the formula Fsp = kx, where x is the displacement of the spring. The initial velocity of the collar is 15 ft/s, and as the collar moves, some kinetic energy is converted into potential energy stored in the spring. The Work-Kinetic Energy Theorem is applied to relate the work done by the spring force to the change in kinetic energy. Since the spring force is variable, an integral must be used to calculate the work done by the spring. Ultimately, the final velocity can be found by solving the energy equation that incorporates the work done by the spring.
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Homework Statement



The 2-lb collar C fits loosely on the smooth shaft. If the spring is unstretched when s = 0 and the collar is given a velocity of 15 ft/s, determine the velocity of the collar when s = 1 ft.

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Homework Equations



F = kx

The Attempt at a Solution



x = l-l0 = (√[1 + s2] - 1) ft

Fsp = kx = [4√(1 + s2) - 4] lb

So, now I've found the spring force, how does velocity fit into this?
 
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Kinetic energy. Some has been given to the spring, whatever is left...
 
Kabbotta said:
Kinetic energy. Some has been given to the spring, whatever is left...

But how do I calculate the velocity?
 
I guess I am a little surprised they gave you a question this hard without even explaining how to calculate kinetic energy.

Work-Kinetic Energy Thm.
K = 1/2mv^2
\sum W = K_{f} - K_{i} + W_{other forces}

The spring force is your other force doing work, and it will be negative work that takes away some kinetic energy, the final kinetic energy contains the velocity you are looking for, but the spring force is not constant so you have to do an integral for the work.

W_{spring} = \int F \cdot dx
 
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