Solve Magnetic Problem: Find Field Magnitude from Radius & Speed

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To find the magnetic field magnitude B from the radius R and speed v of electrons, the equation Fm = q(v × B) is used, leading to the expression Rc = mv / qB. Given the speed of 5.9 × 10^6 m/s and a circular path radius of 2.0 cm, the challenge lies in eliminating the charge q from the equations. The magnetic force acts as the centripetal force, implying that the angle theta is 90 degrees, simplifying the calculations. The discussion emphasizes the need to derive a manageable equation to solve for B without overcomplicating the process.
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Homework Statement



A stream of 100 eV electrons, each with speed v = 5.9 × 106 ms−1, traveling horizontally along the x-axis in the positive x-direction enters a region pervaded by a uniform magnetic field B. The electrons then describe a circle with radius R in the horizontal xy-plane, circulating anticlockwise as viewed from above.
Starting from the equation Fm = q(v × B), derive an expression for the
radius, R, of the circular path followed by the electrons. If R = 2.0 cm, find the magnitude, B, of the uniform magnetic field.

Homework Equations



1. Fm = q(v x B)

2. Rc = mv / qB

3. T = 2 pi mv /vqB = 2 pi Rc / v =2 pim / qB

4. Fm = q v b sin Theta



The Attempt at a Solution


ok the only known variables I have are
v = 5.9 × 106 ms−1
Rc = 2.0

and I know from the next question on my paper that fromthe expression derived I have to evaluate T so therefore T v and Rc must be in the final equation.

The problem I am getting is trying to eliminate q
I started by eliminating Fm by setting equations 1 and 4 =
but the q on the left is magnitude q and the q on the right is not. so I am getting confused now, have rearranged all the equations and substiuting each different variable but the more I carry on I just end up with a HUGE equation I get the feeling that I am making this way too complicated for myself also am I correct in thinking that as the electron showed cyclotronic motion that theta is 90 degrees? help please?
 
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The magnetic force is behaving as centripetal force required to make the path circular.
 
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