Solve Permutation Group Homework: α o β o α-1

[Questioneer]

Homework Statement

This is a problem from a chapter entitled "Permutation Groups" of an abstract algebra text.
1. Let α = ( 1 3 5 7 ) and β = (2 4 8) o (1 3 6) ∈ S₈ Find α o β o α^-1.
2. Let α = ( 1 3) o (5 8) and β = (2 3 6 7) ∈ S₈ Find α o β o α^-1.

Homework Equations

S_n is the set of all permutations on I_n, where I_n={1,2,3,...,n}

Also, o is known to be associative, but not commutative.
α and β are conjugate if there exists γ ∈ S_n such that γ o α o γ^-1 = β

Then, let π = (i₁ i₂ ... i_l) ∈ S_n be a cycle. Then for all α ∈ S_n, α o π o α-1 = (α(i₁) α(i₂) ... α(i_l))

The Attempt at a Solution

I was able to calculate other problems easy enough that did not contain the composition of permutation cycles. Also, I can write the composition as a two row notation instead of a cycle, but then I don't know which elements I use when I calculate the conjugate against alpha. If I left the beta as a composition, maybe I could use the associative property and apply one element first, but I'm at a loss.

A worked out solution would be really great- my professor assigned me 11 of these calculations, saying that they would be "really easy" so this many will not be a big deal. Thanks, prof.

 

[lanedance]

so for the first, note that a will commute with the first cycle of beta

you will also have to have a think about what the inverse of a given cylce is

a nice way to do these problems is as folllows, say you want to examine (23)o(12)which don't commute, but write it out as follows:
start = 1-2-3-4-5-6-7-8
(12) = 2-1-3-4-5-6-7-8
(23) = 2-3-1-4-5-6-7-8 = (123)

note be careful exactly how the cycle is interpreted as they can be written in different ways, I read (123) as 2 goes to 1, 3 goes to 2, and then 1 goes to 3