Solve U1=U*R2/(R1+R2): Current Circuit Theory

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The discussion revolves around the equation U1=U*R2/(R1+R2) in circuit theory, specifically addressing a voltage divider scenario. The confusion arises from the interpretation of current flow and voltage drop across resistors in series. It is clarified that in a series circuit, the current remains constant, thus U1 represents the voltage drop across R2, calculated as U=R2*I. The participant acknowledges that the point where U1 is measured is not connected to any load, meaning no current flows there. Ultimately, the concept of a voltage divider is confirmed as the correct approach to the problem.
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Homework Statement



I want so show that U1=U*R2/(R1+R2) (sorry latex didn't work for me right now, don't know why)



Homework Equations





The Attempt at a Solution



I know the solution but I don't understand one step:
The solution says the following: the fall of voltage at U1 = R2*I (I is the current which comes from U). Why is that? Thats doesn't make sense to me, because I thought the current "splits" at this spot so I have: I=I1+I2.
Why does the solution say it's U=R2*I


Thanks for the help
 

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well u is the emf of the source right ?
but what is this ---------u1 ? wat's U1
 
I don't know how to describe it properly in english, but I think it's the voltage which drains off. I think the english term is voltage divider. But as I'am writing this I think I oversaw something.
The resistances are in series so the current is everywhere the same. Is this the right solution for the problem?
 
That's because the current does not really split.
The point where U1 is measured is not attached to anything, so no current flows.

This is indeed *only* a voltage divider.
Of course, when something (significant) is attached, the currents and voltages will change.
 
Ok, I didn't recognize that I have to handle it this way. Thanks for the help
 
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