Solving 0th-Order Circuit Equations with Two Variables

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The discussion revolves around solving two equations related to a 0th-order circuit with two variables, v1 and v2. The original equations presented by the user contained sign errors, which led to incorrect results. A suggestion was made to rewrite the equations by summing the currents at a node, which improved clarity and accuracy. After corrections, the values for v1 and v2 were determined to be 162V and 200V, respectively, aligning with results from Multisim. The importance of careful sign management in circuit analysis was emphasized throughout the conversation.
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Homework Statement



see attached

Homework Equations


The Attempt at a Solution



0=(v_1-128)/5-V_1/60-(v_2-V_1)/4
0=(v_2-v_1)/4-v_2/80-(v_2-320)/10
I obviously know what the answer should be from multisim but its not coming out. I've tried multiple combinations of this mainly just changing -s to +s because I can never get the current direction right for some reson.

Thanks

edit: the covered up resistor is a 10ohm
 

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pat666 said:

Homework Statement



see attached

Homework Equations





The Attempt at a Solution



0=(v_1-128)/5-V_1/60-(v_2-V_1)/4
0=(v_2-v_1)/4-v_2/80-(v_2-320)/10
I obviously know what the answer should be from multisim but its not coming out. I've tried multiple combinations of this mainly just changing -s to +s because I can never get the current direction right for some reson.

Thanks

edit: the covered up resistor is a 10ohm

Yeah, your signs are kind of strange. I just write the sum of the currents out of a node is equal to zero. Don't do subtractions or whatever you are doing.

So your first equation should be:

(v1-V1)/5 + v1/60 + (v1-v2)/4 = 0

Write out both equations using this form, and see if it all solves up better...
 
Yeah, I had an epiphany last night and started getting these right:)
(v1-128)/5 + v1/60 + (v1-v2)/4 = 0
(v2-V1)/4+v2/80+(v2-320)/10=0

v1=162
v2=320
 
pat666 said:
Yeah, I had an epiphany last night and started getting these right:)
(v1-128)/5 + v1/60 + (v1-v2)/4 = 0
(v2-V1)/4+v2/80+(v2-320)/10=0

v1=162
v2=320

v2 looks wrong. V2 = 320V is the right side source, so v2 has to be less than 320V...
 
oops that's a typo v2 cane out as 200V, I put it in Mathematica and it matched multisim so i assumed that I was correct.
 
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