Solving a 20% Efficient Real Engine Problem

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A 20% efficient real engine accelerates a train to 5.00 m/s, while an ideal Carnot engine can achieve 6.50 m/s using the same fuel, indicating that the Carnot engine is 1.69 times more efficient. The efficiency of the Carnot engine can be expressed as a function of the temperatures of the hot and cold reservoirs. Given that the cold reservoir is air at 27°C, the problem requires calculating the temperature of the steam at the hot reservoir. Understanding that both engines use the same fuel is crucial for determining the relationship between their efficiencies and kinetic energy outputs. This analysis ultimately leads to finding the necessary temperature for the hot reservoir.
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Homework question:

A 20% efficient real engine is used to speed up a train from rest to 5.00m/s. It is known that an ideal (Carnot) engine having the same cold and hot reservoirs would accelerate the same train from rest to 6.50m/s using the same amount of fuel. Assuming that the engines use air at 27C as a cold reservoir, find the temperature of steam at the hot reservoir.

I think what my real problem is is that I'm not sure what the fact that they use the same amount of fuel is telling me. I know that something will be equal between them besides the cold reservoir, but I'm not sure what. The work can't be the same because the final speeds are different.

Can anyone help me to understand this please? Thanks
 
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jaidon said:
Homework question:

A 20% efficient real engine is used to speed up a train from rest to 5.00m/s. It is known that an ideal (Carnot) engine having the same cold and hot reservoirs would accelerate the same train from rest to 6.50m/s using the same amount of fuel. Assuming that the engines use air at 27C as a cold reservoir, find the temperature of steam at the hot reservoir.

I think what my real problem is is that I'm not sure what the fact that they use the same amount of fuel is telling me. I know that something will be equal between them besides the cold reservoir, but I'm not sure what. The work can't be the same because the final speeds are different.

Can anyone help me to understand this please? Thanks
Using the same amount of fuel to accelerate to 6.5 m/s tells you that the ideal Carnot engine would produce 1.69 times more kinetic energy from the same amount of fuel as the real engine does. So it is 1.69 times more efficient.

Since for the Carnot cycle, the efficiency is:
\frac{T_H - T_C}{T_H} (temperatures in Kelvins)
and we know that
Efficiencyideal = 1.69Efficiencyreal
you can work out T_H.

AM
 
jaidon said:
Homework question:

A 20% efficient real engine is used to speed up a train from rest to 5.00m/s. It is known that an ideal (Carnot) engine having the same cold and hot reservoirs would accelerate the same train from rest to 6.50m/s using the same amount of fuel. Assuming that the engines use air at 27C as a cold reservoir, find the temperature of steam at the hot reservoir.

I think what my real problem is is that I'm not sure what the fact that they use the same amount of fuel is telling me. I know that something will be equal between them besides the cold reservoir, but I'm not sure what. The work can't be the same because the final speeds are different.

Can anyone help me to understand this please? Thanks

The same problem and the same answer:
https://www.physicsforums.com/showthread.php?t=51671

I think both of you have used the same book.
 
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