Solving a Carnot Engine Problem: What Unit Do I Use?

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To solve the Carnot engine problem, the correct unit for temperature in thermodynamics is Kelvin. The efficiency of the engine needs to be increased from 31% to 70%, requiring an increase in the high-temperature reservoir's temperature. The calculated increase in temperature is approximately 544.5 K, which is equivalent to 544.5 degrees Celsius. Despite initial attempts using Kelvin, the user found their answer was incorrect, indicating a potential misunderstanding in the application of units. Ultimately, the solution involves using Kelvin for calculations and converting to Celsius for final interpretation.
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I solved the problem, but I can't get the right unit for the answer.

A Carnot engine whose low-temperature reservoir is at 16°C has an efficiency of 31%. By how much should the temperature of the high-temperature reservoir be increased to increase the efficiency to 70%?

My numerical answer is 544.8. I tried Kelvin first - the most obvious choice - but that was wrong. Then I tried celcius and J/K.

I tried to work it out but I have no earthly idea - the other choices include:
- C0 (like the celcius sign but the circle is after the C)
-J/kg*K
-J/mol*K and
-kJ/kg

Any help would be grately appreciated.
 
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sophzilla said:
My numerical answer is 544.8. I tried Kelvin first - the most obvious choice - but that was wrong. Then I tried celcius and J/K.

I tried to work it out but I have no earthly idea - the other choices include:
- C0 (like the celcius sign but the circle is after the C)
-J/kg*K
-J/mol*K and
-kJ/kg

Any help would be grately appreciated.
You have to use Kelvin for temperature in thermodynamics. I get 544.5 K as the increase (from 418.8 K to 963.33 K)

AM
 
Well...the thing is, I did use Kelvin. That was my first choice, but it was wrong. Any other sound possibilities?
 
sophzilla said:
Well...the thing is, I did use Kelvin. That was my first choice, but it was wrong. Any other sound possibilities?
Mind you, this temperature difference is also 544.5 degrees Celsius. It is just that you have to work out the thermodynamics part in K and then convert back to Celsius.

AM
 
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