Solving a Complex Homework Problem: Tip or Slide?

AI Thread Summary
The discussion revolves around calculating the force required to tip over a storage bin weighing 7100 N, with specific dimensions and a friction coefficient of 0.43. Participants emphasize the importance of understanding the pivot point and the direction of opposing forces in determining whether the bin will tip or slide. Key equations involve torque and the relationship between force and distance from the pivot. The conversation suggests that a clear conceptual approach, including visualizing motion and forces, is crucial for solving the problem. Ultimately, the focus is on applying physics principles to analyze the tipping versus sliding scenario effectively.
beijati
Messages
1
Reaction score
0

Homework Statement



I have been trying this question since 5 hours but I am lost ! Any help would be appreciated

Some moron kids are trying to tip over a storage bin as shown. The bin weighs 7100 N, w = 2.2 m, h = 3 m, d = 1.6 m, and theta = 20 degrees. With what force do they need to push in order to tip the bin over?
F= ? Newtons
If the coefficient of friction between the box and the floor is 0.43, calculate the force of friction on the box and determine whether it will slide or tip over
Tip or Slide?

Homework Equations


-T=R∗F∗sin(θ)
ΣT = 0

The Attempt at a Solution


R=sqrt(1.8^2+1.6^2)=2.4m
F=??
R=sqrt(0.9^2+1.5^2)=1.75m
F=7600N
now what??
 

Attachments

  • container.png
    container.png
    31 KB · Views: 640
Physics news on Phys.org


When you do these problems it is helpful to describe what you are doing in words - if nothing else, it focusses you mind on the physics.

What sort of motion does the box have to undergo to get tipped? Where is the pivot?
Where does the main force opposing the tipping act? In which direction?
After that it is a matter of torques and reason - though you could try doing it in terms of conservation of energy.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top