Solving a Frictionless Cart Problem with Rain

AI Thread Summary
A cart on a frictionless surface is initially moving at speed V_0 when it starts collecting rain falling at a rate of q gk per second. The problem involves expressing the cart's speed as a function of time after the rain begins. The equations of motion are set up using the momentum principle, leading to a differential equation that relates the mass of the cart and the rain collected. The suggested approach to solve for the speed involves separating variables and integrating both sides of the equation. The discussion emphasizes the importance of applying initial conditions to find the solution for the cart's speed over time.
Gregie666
Messages
14
Reaction score
0
hi.
can anyone push me in the right direction with the followin problem, please?

Homework Statement


a cart is moving on a frictionless surface at a speed of V_0
the mass of the cart is M.
it suddenly starts to rain at time t=0. the rain is dropping vertically at a rate of q gk per second.
the cart collects all the rain drops that hit it.
express the speed of the cart as a function of time passed since it started raining.

Homework Equations


F = {{dp} \over {dt}}



The Attempt at a Solution


<br /> <br /> <br /> &amp; F = {{dp} \over {dt}} \Rightarrow \cr <br /> &amp; 0 = {{dm} \over {dt}}v(t) + {{dv} \over {dt}}m(t) \Rightarrow \cr <br /> &amp; 0 = qv(t) + {{dv} \over {dt}}(M + qt) \Rightarrow \cr <br /> &amp; qv = - {{dv} \over {dt}}(M + qt) \Rightarrow \cr <br /> &amp; qvdt = (M + qt)dv <br /> <br /> <br />

so i get this equation and i don't know how to solve it for v...


**how do i add line breaks to the latex??**
 
Last edited:
Physics news on Phys.org
just like any differential equation, split the variables, put in the initial conditions, and rearrange for the variable you want.

\int { \frac {q}{M+qt}} dt = \int {\frac {1}{v}}dv

Try it that way
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top