Solving a Limit Involving tanx and pi/4

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Homework Help Overview

The problem involves finding the limit of the expression (tan(x) - 1) / (x - π/4) as x approaches π/4. The subject area is calculus, specifically limits and trigonometric functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss rewriting the limit using trigonometric identities and question the use of L'Hôpital's rule. There is uncertainty about how to proceed after initial transformations, with some suggesting to express tan(x) in terms of (x - π/4).

Discussion Status

The discussion is ongoing, with participants providing different approaches to rewriting the limit. There is no explicit consensus yet, but some guidance has been offered regarding the use of trigonometric identities.

Contextual Notes

There is a mention of potential restrictions on using L'Hôpital's rule, which may influence the approaches being considered. Participants are also grappling with the implications of substituting π/4 into the limit expression.

Glissando
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Homework Statement


Find the limit:

lim (tanx-1)/(x-pi/4)
x->pi/4


Homework Equations


tanx = sinx/cosx


The Attempt at a Solution



lim (sinx/cosx-1)/(x-pi/4)
x->pi/4

lim [(sinx-cosx)/cosx]/(x-pi/4)
x->pi/4

I have no idea what to do after this ): I also tried squaring the whole function and getting tan2x-1 = sec2x, but I get so lost on what to do with pi/4 because it just keeps becoming undefined!

Thanks for your help!
 
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Hi Glissando! :smile:

I take it you're not allowed to use l'hospital's rule?? In that case, I would first write

[tex]\tan(x)=\tan((x-\pi/4)+\pi/4)[/tex]

and work that out. That way you can write everything in function of [itex]x-\pi/4[/itex].
 
micromass said:
Hi Glissando! :smile:

I take it you're not allowed to use l'hospital's rule?? In that case, I would first write

[tex]\tan(x)=\tan((x-\pi/4)+\pi/4)[/tex]

and work that out. That way you can write everything in function of [itex]x-\pi/4[/itex].

Hi micromass,

Thanks for your quick response! I'm not too sure what you mean by working it out...do I plug that back into the original equation? Am I solving for x?

Thanks!
 
Well, you know formula's for [itex]\tan(\alpha+\beta)[/itex]. So apply these formula's on

[tex]\tan((x-\pi/4)+\pi/4)[/tex]

Our goal is to write everything in function of [itex]x-\pi/4[/itex]
 

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