Solving Calculus Derivatives at a Specific Point

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F(5) =1 , F'(5)=6, G(5)=-3 and g'(5)=2 Find the value

(\frac{f}{g})'(5) = ?

Answer is -\frac{20}{9}.

Can anyone shows the way to solve this?
 
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http://en.wikipedia.org/wiki/Quotient_rule" helps?
 
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i guess not...
 
You need to apply the Quotient Rule for derivatives,
\frac{d}{dx} \left(\frac{f(x)}{g(x)}\right) = \frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}

You're given certain information on two functions. How can you use that information to find the derivative of the quotient of the two functions?

This is obviously a homework question. We won't solve your homework for you, only point you in the right direction.
 
sorry for posting the wrong place, will change the place.

I am not sure why they ask such a question.

I am not expecting others to do my homework but only wants other people to show me the direction.
 
tee yeh hun said:
I am not sure why they ask such a question.

These questions are designed to test one's knowledge of the various rules of differentiation, in this case the quotient rule.

All you really need to do is plug in the proper values.
 
oh!... i got it already , thank you
 
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