Solving Dynamics Question: F_spring & F_spring Potential

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The discussion centers on understanding the relationship between spring force and spring potential energy in a dynamics problem. The spring force is defined as F_spring = ks, while the potential energy is given by F_spring potential = 1/2 ks^2. A participant mistakenly equates the spring force directly with the potential energy formula, leading to an incorrect calculation of stretch. Instead, the correct approach is to determine the stretch based on the known force and spring constant, which reveals the potential energy. Clarifying the distinction between force and potential energy is crucial for solving the problem accurately.
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Homework Statement


Screen Shot 2017-06-18 at 1.34.48 PM.png


Homework Equations



F_spring = ks and F_spring potential = 1/2ks^2

The Attempt at a Solution



So I recognize that @ theta = 0 it is a 3/4/5 triangle. The length of the spring is at .5m...furthermore the given spring force at that angle is 100 N. So why is it wrong to do 100 = (1/2) (500) (s)^2 ==>> s = .632m... Why should I use F= ks

Everything else I understand...
 
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Maybe I don't understand what you're trying to do, but it looks like you're plugging in the force of the spring where the potential energy should go.

If you know that the spring applies 500 Newtons for every meter its stretched, if it's applying 100 Newtons, it must have been stretched 0.2 meters (and therefore its normal length is 0.3 meters). That would allow you to find the potential energy in the spring. (Again, if I'm misunderstanding the problem, please tell me).
 

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