Solving Energy Dissipation in Lightbulbs Connected to a Power Line

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SUMMARY

The discussion focuses on calculating the energy dissipation in lightbulbs rated at 40 W, 60 W, and 100 W connected to a 120 V/60 Hz power line. The relevant equation used is Pr = (Vrms)^2/R, where Vrms is the root mean square voltage and R is the resistance of each bulb. Participants emphasize the need to find the resistance of each lamp and the equivalent resistance of the circuit to determine the current in each branch. The energy dissipated in each lamp is calculated using the formula I^2*R.

PREREQUISITES
  • Understanding of electrical power equations, specifically Pr = (Vrms)^2/R
  • Knowledge of how to calculate resistance for lightbulbs based on their wattage
  • Familiarity with circuit analysis techniques, including equivalent resistance
  • Basic understanding of current flow in parallel circuits
NEXT STEPS
  • Calculate the resistance of each lightbulb using their wattage ratings and the formula R = Vrms^2/Pr
  • Learn about equivalent resistance in parallel circuits to analyze multiple branches
  • Explore the concept of root mean square (RMS) voltage and its application in AC circuits
  • Study the relationship between current, voltage, and resistance using Ohm's Law
USEFUL FOR

Students studying electrical engineering, educators teaching circuit analysis, and anyone interested in understanding energy dissipation in electrical components.

Mitchtwitchita
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Homework Statement



Lightbulbs labeled 40 W, 60W, and 100 W are connected to a 120 V/60 Hz power line as shown in the diagram. What is the rate at which energy is dissipated in each bulb?



Homework Equations



Pr = (Vrms)^2/R

The Attempt at a Solution



I'm not exactly sure how to get this one started. Do I have to make some sort of equivalency lightbulb? Can somebody please point me in the right direction?
 

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Voltage across each branch is the same. Using the relevant equation find the resistance of each lamp.

Find the equivalent resistance of the circuit and the current in each branch.

Energy dissipated in each lamp is given by I^2*R.

Now proceed.
 
Thanks a bunch rl.bhat!
 

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