Solving Escalator Motion Problems: A Shopper's Guide

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To solve the escalator motion problem, the key is to understand the relationship between the shopper's speed, the escalator's speed, and the time taken to traverse the distance. The shopper's speed on the stationary escalator is L/8 m/s, while the escalator's speed is L/15 m/s. To find the time it takes to walk up the moving escalator, one must combine these speeds. Additionally, the discussion raises the question of whether the shopper can walk down the moving escalator and the time required for that as well. Understanding these dynamics is crucial for solving the problem effectively.
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I really do not understand this question...what kind of formula can I use, because there is no displacement/distance? any help? What do I do since there is only one variable? thanks in advance.

QUESTION: A shopper can ride up a moving escalator in 15 s. When the escalator is turned off, the shopper can walk up the stationary escalator in 8 s. a) How long would it take the shopper to walk up the moving escalator? b) Could the shopper walk down the moving escalator to the floor below? if so how long would it take?
 
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sultaN-PL said:
I really do not understand this question...what kind of formula can I use, because there is no displacement/distance? any help? What do I do since there is only one variable? thanks in advance.

QUESTION: A shopper can ride up a moving escalator in 15 s. When the escalator is turned off, the shopper can walk up the stationary escalator in 8 s. a) How long would it take the shopper to walk up the moving escalator? b) Could the shopper walk down the moving escalator to the floor below? if so how long would it take?
The speed of the escalator is +L/15 m/sec where L is the length in metres. Her speed relative to the escaltor is + or - L/8 (m/sec). Her speed relative to the ground is _____? The distance is L. So how long does that take?

AM
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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