Solving Explosion Problem: Calculate Kinetic Energy of Horizontal Piece

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The problem involves a 50 kg projectile that explodes into three pieces, with one piece moving horizontally at 150 m/s. The kinetic energy of the horizontally moving piece is calculated using the formula KE=(1/2)mv^2, leading to a correct answer of 375,000 J. A misunderstanding arises regarding the distribution of mass among the pieces, as the center of mass must remain at the original speed of 100 m/s. The discussion highlights the importance of balancing the velocities of the pieces to maintain the center of mass's momentum. This problem serves as an example of applying conservation principles in explosion scenarios.
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1. A projectile of mass 50 kg moving horizontally at 100m/s explodes into three pieces. Two pieces fly off vertically while a third continues horizontally at 150m/s (neglect gravity).

What is the kinetic energy of the horizontally moving piece?



2. Homework Equations

KE=(1/2)mv^2
W=∆KE
W+KEi + PEi =KEf + PEf
PE=mgh

3. The Attempt at a Solution

W=∆KE
=(1/2)mvf^2-(1/2)mvi^2

But I got incorrect answer. The correct answer is 375000 J
 
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This is a good problem. Does the mass break apart equaly because I keep getting half of the KE (187500J) I am doing .5(50/3)(150)^2. Anyone have any input
 
The problem does not say, but that is the number I kept getting as well. 1875000 is half of 375000, but I am not sure if that is relevant to what we are doing wrong.
 
This looks like a Center of mass problem doesn't it?

What you know is that at the moment of explosion you have 2 pieces that fly off, presumably 1 up and the other down of indeterminate mass and velocities in the vertical direction. But the piece of interest continues horizontally only faster.

So ... don't you know that the center of mass is continuing at 100 m/s and now the horizontal piece is moving at 150 m/s?

How must you balance that out such that the center of mass continues at the original 100 m/s, because that's what it will be doing won't it?
 
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