Solving for Distance of a Rotating Wheel

  • Thread starter Thread starter julz3216
  • Start date Start date
  • Tags Tags
    Rotating Wheel
Click For Summary

Homework Help Overview

The problem involves calculating the distance traveled by a point on the edge of a rotating wheel that accelerates uniformly from a specified initial to final angular velocity over a given time period. The subject area includes rotational motion and angular kinematics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of angular kinematic equations and the need to convert angular velocities from rpm to radians per second. There is an exploration of calculating angular acceleration and the total angle rotated during the acceleration period.

Discussion Status

Some participants have provided guidance on unit conversion and the correct application of formulas. There is an acknowledgment of potential errors in calculations and the importance of using consistent SI units. Multiple interpretations of the calculations are being explored, but no consensus has been reached on the final answer.

Contextual Notes

Participants note the importance of maintaining SI units throughout the calculations, with specific reference to the diameter of the wheel being in meters rather than centimeters.

julz3216
Messages
18
Reaction score
0

Homework Statement



A wheel 31.8 cm in diameter accelerates uniformly from 242 rpm to 380 rpm in 7.66 s. How far will a point on the edge of the wheel have traveled in this time?


Homework Equations



angle = initial angle +angular velocity(t) + .5(angular acceleration)(t)

w=initial angular velocity +angular acceleration (t)

and s=R*angle

The Attempt at a Solution



i tried plugging into the equations but i really don't know what to do
 
Physics news on Phys.org
angle = initial angle +angular velocity(t) + .5(angular acceleration)(t)
Not quite.

θ = θo + ω*t + 1/2*α*t2

Where θ is in radians.

And there are 2π radians in a revolution.

First convert your ω's to radians/sec from rpm and figure α and then you can figure your θ.

To find distance ... x = θ *r
 
I converted to rad/sec so its 25.34 and 39.79
I found a = (39.79-25.32)/7.66 =1.886
then I used θ = θo + ω*t + 1/2*α*t2
and did θ = 0 + 25.34*7.66 + 1/2*1.886*7.66 = 249.435

So i got x=θR = 249.435(15.9) = 3966.01

But this is wrong, is there something else I need to convert or calculate?
 
julz3216 said:
But this is wrong, is there something else I need to convert or calculate?

Without doing any other math I would note the diameter is .318m.

Always, always stay in SI units wherever possible.
 
Oh ok, that's what I did wrong. I got it. Thank you!
 

Similar threads

Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
16
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
19
Views
3K
  • · Replies 44 ·
2
Replies
44
Views
7K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K