Solving for I2 in a Circuit: What Am I Doing Wrong?

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The discussion revolves around solving for three currents (I1, I2, I3) in a circuit using loop and junction analysis. The participant initially struggles with their calculations and the setup of their loop equations, particularly regarding the identification of junctions and loops. They realize that only two loops and one junction are necessary to solve for the currents, leading to confusion about their previous approach. After correcting the identification of nodes, they successfully solve for the unknown currents. The focus shifts from setup issues to ensuring accurate calculations based on the revised circuit diagram.
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Homework Statement


I am attempting to solve the circuit for three currents (I1, I2, I3). I am starting with I1 in terms of I2, then using a third equation to solve for I2 in terms of E and R. I wrote my loops at the bottom of the page. I am using Loop 1 @ B, Loop 2 @ B, and Junction at B to solve for I2.
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Homework Equations


ΣIin=ΣIout
∫dv=0

The Attempt at a Solution


Page 2 has all my algebra to solve for I2 first. I reversed the sign of Loop 3 at B, but I don't think that is what is throwing off my answer. I have a measured I2 value to compare against and my answer is nowhere near it. Not sure what I am doing wrong.
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The first issue is that A is not a junction. Also the system looks over determined. There are only two loops so you only need two currents.
 
Thank you for your reply. This is a lab experiment so I have to follow (i.e. use) the circuit diagram I am given. You are absolutely right, I need only the two loops and one junction at B to solve for the 3 currents. I am more looking to see if my loop equations are setup correctly. Then I can move on to what I did wrong in my calculations.
 
Okay, in that case the nodes A and C are incorrect.
 
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Thank you for your observation. I was able to correct the nodes and solve for each unknown current. Even found out how to solve using only one node!
 
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