Solving for Initial Velocity Up a Plane: A Homework Problem

AI Thread Summary
The discussion revolves around solving a physics homework problem involving a carton moving up a 22-degree incline with an initial speed of 3.0 m/s. Participants clarify that the problem requires breaking it into two equations, focusing on forces in the x and y directions. The acceleration in the x direction can be derived from gravitational components, specifically using a_x = g*sin(theta). After determining the distance and time to reach the maximum height, it is suggested to double this time to find the total time for the carton to return to its starting point. The conversation emphasizes understanding the relationship between initial velocity, acceleration, and time in projectile motion.
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Homework Statement


A carton is given an initial speed of 3.0 m/s up a 22.0 degree plane. a.) How far up the plane will it go? b.) How much time elapses before it returns to its starting point? Ignore friction.

Homework Equations


F=ma


The Attempt at a Solution


I have no clue. If someone could point me in the right direction and try to explain what's going on I would very much appreciate it.
 
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I've been trying to figure it out. I know I'm supposed to break it into 2 equations, but I don't know how to express the 3.0 m/s velocity in the x equation.

\sumFx=mg*sin\theta=max

\sumFy=FN-mg*cos\theta=may=0

Is that right? If it is I still don't know where to go from here
 
Use the equation vf^2 = vi^2 + 2(a_x)(s).
 
But I don't know the time, nor the acceleration.
 
You have both the initial and final velocities so all you need right now is the acceleration in the x direction, which you can find by using mg = Fncos(theta) and a_x = gsin(theta).
 
Oh, ok. Now I get it. You put an (s) in the equation which threw me off. I found the distance and the time it took to reach the max point, but how do I get the total time? Should I just double the time it took to get to the highest point?
 
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