Solving for linear mass density of a string

AI Thread Summary
To solve for the linear mass density of a string, the key equations involved are μ = M/L and the wave speed equation v = √(T/μ). The approach involves deriving expressions for frequency in terms of the number of segments and the slope of the frequency plot. By manipulating these equations, the final expression for linear mass density can be represented as μ = T/((df/dn) * 2L)², where df/dn is the slope of the frequency vs. number of segments plot. This method effectively incorporates the tension and length of the string into the calculation of linear mass density.
AToMic93
Messages
6
Reaction score
0
HELP: Solving for equation of linear mass density of a string

Homework Statement


You will plot frequency vs. number of segments and determine a slope. Write the expression which will allow you to solve for the linear mass density of the string in terms of L, T, and the slope of your plot

Homework Equations


1) μ=M/L
2) T=2∏√(m/k) ?
3) λ=2L/n
4) df/dn=?
5) k=2∏/λ

The Attempt at a Solution


So what I've done is take equation 2 solve for m which is m=(T/2∏)2*k, with substitution from equation 5, then substitution from equation 3 to get the equation:
m=(T2*n)/(4∏L) which I substituted into equation 1 to get:
μ=(T2*n)/(4∏L2)
So so far I have the equation in terms of L and T but not in terms of the slope of my plot which would be df/dn.

Thanks!
 
Last edited:
Physics news on Phys.org
So I completely redid the problem a different way and I think this is right. Let me know if it is or not:
Equations:
1) v=√(T/μ)
2) v=(2Lf)/n

Attempt at solution:
Solve equation 1 for μ=T/v2, then solve equation 2 for f=vn/2L. Then derive f equation to get in terms of df/dn (slope of graph)= v/2L, solve for v, v=(df/dn)*2L and plug into the equation for μ to get μ=T/((df/dn)*2L)2.
This works right?
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top