Solving for Rotational Velocity of a Ring and Bug System | Homework Question

  • Thread starter Thread starter aigerimzh
  • Start date Start date
  • Tags Tags
    Mass Ring
aigerimzh
Messages
15
Reaction score
0
1. Homework Statement

A ring of mass M and radius R lies on its side on a frictionless table. It is pivoted to the table at its rim. A bug of mass m walks around the ring with speed v, starting at the pivot. What is the rotational velocity of the ring when the bug (a) is halfway around and (b) back at the pivot?

2. Homework Equations

p=mv

3. The Attempt at a Solution

If I assume that only momentum and angular momentum are conserved, and that the bug still has speed v with respect to the ring, I get these equations:

-mv = m(v + V) + Mv
-mRv = -mR(v + V) + M(R^2)(omega)

where V is the velocity of the ring and omega is the angular velocity. I solve these equations for omega, and I don't get the answer in the book.

Where did I go wrong? Thanks in advance for all your help.
 

Attachments

  • 161020114598.jpg
    161020114598.jpg
    17.2 KB · Views: 570
Last edited:
on Phys.org
"It is pivoted to the table at its rim."

What does this mean?
 
LawrenceC said:
"It is pivoted to the table at its rim."

What does this mean?

It is in attached picture
 

Similar threads

Replies
335
Views
19K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
10K
Replies
39
Views
4K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K