Solving for Series Resonance at 50Hz with Impedance and Inductance Calculations

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SUMMARY

The discussion focuses on calculating the inductance required for a circuit to achieve series resonance at a frequency of 50Hz. The AC generator provides a voltage of 230<45º volts across an impedance of 17.4<-33º ohms. The relevant equation used is 1/2πfc = 2πfl, leading to the calculation of current (I) as 9.47 A and capacitance (C) as 3.36x10^-6 F. The user seeks clarification on the inductance calculation to ensure resonance is achieved.

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  • Familiarity with impedance and its representation in polar form
  • Knowledge of resonance in electrical circuits
  • Proficiency in using the formula 1/2πfc = 2πfl
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Homework Statement



An AC generator produces a voltage of 230<45º volts. It is connected across an impedance of 17.4<-33º ohms.

The supply frequency = 50Hz


I got my assignment back and this question wrong, maybe you can guide me, please because I’m not sure entirety. Help is appreciated.

Question: Calculate the value of inductance that will make the circuit become series resonant at 50Hz?


Homework Equations



1/2π fc = 2 π fl

The Attempt at a Solution



I= 17.4 sin33 = 9.47
C= 1/2 π (50x9.47) = 3.36x10^-6
Would it be: 2 π fl > 2 π(50) = 314 ?
 
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