Solving for Tension & Acceleration of Forces in Diagram

AI Thread Summary
The discussion focuses on solving for tension and acceleration in a system of three masses using free body diagrams (FBD). The user has derived three equations for acceleration based on the forces acting on each mass but is unsure how to proceed with solving them simultaneously. A suggestion is made to substitute expressions for tensions from two equations into the third to simplify the problem. The user expresses concern about obtaining an unexpected result, indicating a potential algebra error. The importance of verifying calculations by substituting values back into the original equations is emphasized to check for mistakes.
Tensaiga
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i drew a digram for the forces and i found out the equations for accerleration... then I'm stuck...

Question: Determine the tension in the strings, the acceleration, and how far the masses will go in 2.0s. (See attachement)

Well i drew a FBD, ,and i got three eqations for accerleration:
for mass 1 (100g):
A = (T2 - M1*G)/(M1)
A = (T2 - 0.1*9.8)/(0.1)

mass 2: (200g, on the floor)
A = (T1 - T2)/(M2)
A = (T1 - T2)/(0.2)

mass 3: (200g, going down on the right)
A = (M3*G - T1)/(M3)
A = (0.2*9.8 - T1)/(0.2)

Then what should i do after this? i can't equate 3 equations at once... can i?
 

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Tensaiga said:
i drew a digram for the forces and i found out the equations for accerleration... then I'm stuck...

Question: Determine the tension in the strings, the acceleration, and how far the masses will go in 2.0s. (See attachement)

Well i drew a FBD, ,and i got three eqations for accerleration:
for mass 1 (100g):
(1) A = (T2 - M1*G)/(M1)
A = (T2 - 0.1*9.8)/(0.1)

mass 2: (200g, on the floor)
(2) A = (T1 - T2)/(M2)
A = (T1 - T2)/(0.2)

mass 3: (200g, going down on the right)
(3) A = (M3*G - T1)/(M3)
A = (0.2*9.8 - T1)/(0.2)

Then what should i do after this? i can't equate 3 equations at once... can i?
Why not? After all, if the string does not break the accelerations are all the same. Try inserting the expressions for T1 and T2 from equations 1 and 3 into 2. That will give you an equation with only one unknown: A.

AM
 
yea i tried that, but a strange number came out... i will try again, maybe it's a algebra error.
 
Tensaiga said:
yea i tried that, but a strange number came out... i will try again, maybe it's a algebra error.
Your equations look right. Did you solve for both tensions and for the acceleration? If so, there is an easu way to tell if you made an algebra mistake: just plug back your values in the initial equations! If it does not work, it shows that you made an algebra mistake.

Patrick
 
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