Solving for the Mass and Velocity of a Puck After a Perfectly Elastic Collision

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In a perfectly elastic collision involving a blue puck and a red puck, the blue puck has a mass of 0.044 kg and an initial speed of 0.250 m/s, while the red puck is initially at rest. After the collision, the blue puck's speed decreases to 0.050 m/s. To find the mass and velocity of the red puck, one can apply the conservation of momentum and kinetic energy principles, resulting in two equations with two unknowns. The discussion emphasizes the importance of recognizing key terms like "perfectly elastic collision" to apply the correct conservation laws. Utilizing these principles will lead to the solution for both variables.
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A blue puck with a mass of 4.40*10^−2kg , sliding with a speed of 0.250m/s on a frictionless, horizontal air table, makes a perfectly elastic, head-on collision with a red puck with mass x, initially at rest. After the collision, the velocity of the blue puck is 5.00*10^−2m/s in the same direction as its initial velocity.

It asks me for both the mass and the velocity of the red puck.

Well, since neither mass nor velocity is given to me, should I use P=m*v to find the momentum lost and then transfer it to the red puck? Or do I just derive an equation from momentum conservation and plug that into another momentum conservatio equation so I only have one unknown variable, and solve for that? Please advise.

Thanks.
 
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Since u're dealing with an ideally elastic collision,by applying correctly the laws of momentum & KE conservation,u'll get exactly 2 equations for the 2 unknowns:mass & speed.

Daniel.
 
Oooh, KE conservation. Thanks. I will try that out now. I always seem to forget about these things every once in a while.
 
You should always look for key words."perectly elastic collision" automatically means KE conservation (ok,no relativistic efects);

Daniel.
 
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