Solving for x: Graph of y=|2x|-|3-x|

  • Thread starter Thread starter ][nstigator
  • Start date Start date
  • Tags Tags
    Graph
AI Thread Summary
The discussion focuses on solving the equation |3x+2|=2|3-x| and sketching the graph of y=|2x|-|3-x|. Participants suggest setting y=2 in the graph to find intersections, leading to the solutions of |2x|=|3-x|+2. The graph intersects at the points (1.67, 2) and (-5, 2), resulting in the solutions x=5/3 and x=-5. The conversation emphasizes verifying these solutions against the original equation.
][nstigator
Messages
24
Reaction score
0
1a
Solve for x:
|3x+2|=2|3-x|

Done that part

b
Sketch the graph of y=|2x|-|3-x| and hence find all solutions of
|2x|=|3-x|+2

I have sketched the graph however I don't know what to do for "and hence find all solutions of
|2x|=|3-x|+2"

Please help :D Any help would be much appreciated
 
Physics news on Phys.org
Set y = 2 in your graph, and you'll arrive at the same equation. Draw a horizontal line at y = 2 and see where it crosses the graph.
 
intersects at (1.6666666666666,2) and (-5,2)
 
][nstigator said:
intersects at (1.6666666666666,2) and (-5,2)

Correct. So x = 5/3 or x = -5. Check it against the equation.
 
ah k coolies :D
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top