Solving for $z_1^*$: Argand Diagram

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    Argand Diagram
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Discussion Overview

The discussion revolves around the interpretation of the notation $z_1^*$ in the context of complex numbers, specifically regarding its representation on an Argand diagram. Participants explore the meaning of the star symbol and its relation to complex conjugation.

Discussion Character

  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions whether the star symbol is a typo or has a specific meaning.
  • Another participant suggests that if $j$ represents $\sqrt{-1}$, the star likely indicates complex conjugation, defining $z^{\ast}$ as $a - jb$ for $z = a + jb$.
  • A participant expresses agreement with the interpretation of the star symbol and notes their surprise at encountering it without prior explanation.
  • It is mentioned that the "overline" notation is more common for complex conjugation, but the asterisk is also used.

Areas of Agreement / Disagreement

Participants generally agree that the star symbol represents complex conjugation, although there is some discussion about its notation and usage. No consensus is reached on the necessity of prior explanation for its meaning.

Contextual Notes

The discussion does not resolve whether the star symbol is universally understood or if its use varies among different contexts.

fordy2707
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hi all,hope I find you all well and that I've posted this in the correct section

ive been given this $z_1$ =1-j2

Question ,find and show the result of $z_1 ^*$ on an argand diagram ,my question is what does the star symbol represent or is it a typo?

many thanks
 
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fordy2707 said:
hi all,hope I find you all well and that I've posted this in the correct section

ive been given this $z_1$ =1-j2

Question ,find and show the result of $z_1 ^*$ on an argand diagram ,my question is what does the star symbol represent or is it a typo?

many thanks

If $j$ is meant to represent $\sqrt{-1}$, then the star most likely represents complex-conjugation, so that if:

$z = a + jb$ (with $a,b \in \Bbb R$)

then $z^{\ast} = a - jb$ (we replace the imaginary part with its negative).
 

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I don't think it's a typo-see my earlier post.
 
Yep I'm with you, thanks.i looked up the wording you used and found this to certainly be the case many thanks for the help.it amazes me that I have this thrown into my questions without any prior explanation of its meaning.
 
The "overline", [math]\overline{z}[/math] is more common but, yes, the asterisk is sometimes used to indicate the complex conjugate. If [math]z= x+ iy[/math], then [math]z^*= \overline{z}= x- iy[/math].
 

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