Solving Gun Shot Question: Average Horizontal Force Applied to Gun

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Homework Statement


A rifle is held rigidly by a supporting test frame. When fired horizontallly, a 50 g bullet attains a muzzle exit velocity of 500 m/s if it takes 0.003 s for the bullet to travel the length of the barrel, determine the average horizontal force applied to the gun by the test frame during firing.



Homework Equations





The Attempt at a Solution



I know that the answer is 8.33 kN but I do not know how to solve it.
I think that we evaluate the forces on the x axis, there are no forces on the y-axis but
i am not sure, any help?
 
  • #2
I know that the answer is 8.33 kN

Hint: 8330 is half of 50/.003.
 
  • #3
lol, so i multiply 50/0.3 by a half? Thanks for the help but can you tell me what steps i should take, i really do not get this problem.
 
  • #4
F = ma

With what you're given, how can you find the acceleration?

You have the mass, but you have to change it's units so you can get the force in Newtons (N).
 
  • #5
(i must admit i think it's a badly-worded question, and i don't really understand the mechanical set-up :frown: … but what they obviously want is …)

ok … Newton's second law …
force = mass times acceleration​
so …
average force = mass times average acceleration …​

and average acceleration is … ? :smile:
 
  • #6
In order to find the average force we need to know the average acceleration,to find the average acceleration we divide 500/0.003, which is velocity divided by time. This comes out to be 166666.667., then we multuply by 50, correct? I`m sorry if i am wrong but I am really trying to answer this based on the help you are giving me, do we find average acceleration by a different method?
 
  • #7
In order to find the average force we need to know the average acceleration,to find the average acceleration we divide 500/0.003, which is velocity divided by time. This comes out to be 166666.667., then we multuply by 50, correct?

No … 1 N = 1 kg m /s² … so we multiply by 0.05. :smile:
 

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