Solving Ideal Gas Law Problem: Volume of Rigid Container at 1.20 atm and 60.0°C

AI Thread Summary
To find the volume of a rigid container holding 2.80 mol of gas at 1.20 atm and 60.0°C, the ideal gas law equation PV=nRT is used. The initial calculation yielded an unreasonably large volume of 6457 m³, prompting a reevaluation of units. It was clarified that the gas constant R should be used with compatible units, specifically Joules per mole per Kelvin (J/mol*K), which requires pressure to be in N/m² instead of atm. This adjustment led to a better understanding of the correct units needed for the calculation. Ultimately, ensuring consistent units is crucial for solving ideal gas law problems accurately.
BryceHarper
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Homework Statement



A rigid container holds 2.80 mol of gas at a pressure of 1.20 atm and a temperature of 60.0 degrees Celsius. What is the container's volume?


Homework Equations



PV=nRT

The Attempt at a Solution



(2.80*8.31*333)/1.20 = 6457m^3

This answer seems way too big, what am I doing wrong?
 
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Watch units.
 
Should use N/m^2 rather than atm?
 
Should I**
 
When you write 8.31 for R, what are the units that go with that number?
 
J/mol*K
 
What system of units uses Joules, moles, and Kelvins? Then decide what the units of pressure are for that system of units.
 
Ahhhh okay, I got it now. Thanks!
 
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