Solving LaGrange Multipliers for Closest Points to Origin on xy+yz+zx=3

wilcofan3
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Homework Statement



Consider the problem of finding the points on the surface xy+yz+zx=3 that are closest to the origin.

1) Use the identity (x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx) to prove that x+y+z is not equal to 0 for any point on the given surface.

2) Use the method of Lagrange multipliers to find a system of four equations in x,y,z and \lambda whose solutions will give the closest points.

3) Find the points on xy+yz+zx=3 that are closest to the origin.

Homework Equations


The Attempt at a Solution



I'm clueless on what to do for the 1st part (although I imagine it's actually something simple), but I think I have the second part down. Problem is, I think I probably need to use the 1st part for the 3rd somehow.

For the second part, I found the system of four equations to be:

2x=\lambda(y+z)
2y=\lambda(x+z)
2z=\lambda(x+y)
xy+yz+zx=3
 
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For part 1: HINT - Use the fact that for any point on the surface xy + yz + xz = 3

For part 3: HINT - Add the left sides of the first three equations and their right sides to make a new equation (then use part 1)
 
wilcofan3 said:
Problem is, I think I probably need to use the 1st part for the 3rd somehow.
You can use the first part, even if you don't know why the first part is true. :-p

By the way, part 3 is just a system of equations, solve it the way you normally would. The first part doesn't really affect that -- all ithe first part does is let you make a simplification along the way.
 
Hurkyl said:
You can use the first part, even if you don't know why the first part is true. :-p

By the way, part 3 is just a system of equations, solve it the way you normally would. The first part doesn't really affect that -- all ithe first part does is let you make a simplification along the way.

I feel so stupid, I'm failing at solving this simple system, yet I am pretty sure I know what I'm going to end up with. I'm sure it will be something like x+y=-z that I end up with, because than that would say x+y+z=0 which isn't true, which proves that x=y.

EDIT: Nevermind, it's solved. I don't know why I was blanking on solving the system.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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