Solving Linear Algebra Homework: Help Needed!

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SUMMARY

This discussion focuses on solving linear algebra homework involving vector projections and the column space of matrices. Key equations mentioned include ||a|| = sqrt(ATA) and methods for finding the projection of a vector onto a subspace. The process involves constructing a basis for the subspace, extending it to a basis for the entire space, and then expressing the given vector in that basis. The discussion emphasizes using independent column vectors as a basis when applicable.

PREREQUISITES
  • Understanding of linear algebra concepts such as vector projections.
  • Familiarity with matrix operations and column spaces.
  • Knowledge of basis vectors and subspaces.
  • Ability to interpret mathematical equations and expressions.
NEXT STEPS
  • Study the concept of vector projections in linear algebra.
  • Learn about constructing bases for subspaces in vector spaces.
  • Explore the properties of column spaces in matrices.
  • Review the application of the equation ||a|| = sqrt(ATA) in vector analysis.
USEFUL FOR

Students studying linear algebra, educators teaching vector spaces, and anyone needing assistance with vector projections and matrix column spaces.

madmax2006
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Homework Statement


http://img136.imageshack.us/img136/8452/linalg.png


Homework Equations



I'm trying to figure out what it's asking me to do, as soon as I figure that out, I maybe be able to figure out the equation...

We've gone over stuff like finding the Vector OQ(->) on something like this..
http://img24.imageshack.us/img24/8452/linalg.png

Anybody have a clue what it's asking?

I've seen equations like;
||a|| = sqrt ( ATA)

and

http://img689.imageshack.us/img689/8452/linalg.png

and some others.. Thanks
 
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The "column space" of matrix A is the subspace spanned by its columns. One way to find the projection of a vector on a subspace is:

Construct a basis for the subspace.
Add vectors to extend to a basis for the entire space.
Write your given vector in that basis.

Drop the terms involving basis vectors not in the subspace.

In this case, if the columns themselves are independent vectors, you can use the column vectors as your basis for the subspace.
 

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