Solving Nonideal Voltmeters with R_V, r, and E

  • Thread starter Thread starter evilempire
  • Start date Start date
AI Thread Summary
The discussion focuses on calculating the potential difference measured by a voltmeter connected to a battery with internal resistance. The user initially struggles with two equations involving the battery's emf, internal resistance, and voltmeter resistance. They successfully solve for the voltmeter reading but then encounter a new challenge regarding the minimum resistance required for accurate readings within 1.0% of the emf. The user ultimately resolves this issue as well, indicating they no longer need assistance. The thread concludes with the user expressing satisfaction in solving their problems.
evilempire
Messages
24
Reaction score
0
Here is the question, for reference:

A voltmeter with resistance R_V is connected across the terminals of a battery of emf E and internal resistance r. Find the potential difference Vmeter measured by the voltmeter.
Express your answer in terms of R_V, r, and E.

I have two equations but am having trouble solving them for V, clearly by eliminating I

E-(I*r)-(I*R_V)=0
V_ab=E-(I*R)

Any help would be appreciated, thanks.
 
Physics news on Phys.org
Nevermind, I got it, but the next problem is giving me a bit of trouble:

If E = 7.5 volts and r = .45 ohms, find the minimum value of the voltmeter resistance R_V for which the voltmeter reading is within 1.0% of the emf of the battery.

I am given the following equation to work with:

E(1-(r/(r+R_V))
 
Nevermind, got that too. Disregard this thread, heh.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top