Solving Part B of Homework Equation | Φ, EMF & V

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Homework Help Overview

The discussion revolves around a physics problem related to electromotive force (EMF), magnetic flux (Φ), and the relationship between area and speed in a moving coil scenario. Participants are examining the calculations and concepts involved in Part B of a homework assignment.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of magnetic flux and its relation to EMF, questioning the transition from Φ to dΦ/dt. There is an exploration of how area and speed are connected in the context of the problem.

Discussion Status

Some participants have provided insights into the relationship between the area of the loop and the speed of the coil's movement. There is an ongoing exploration of how these elements interact, with no explicit consensus reached yet.

Contextual Notes

Participants are working with specific values and conditions, such as the dimensions of the loop and the speed of movement, which may influence their calculations and understanding of the problem.

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Homework Statement


Uploaded the question below , Part B

Homework Equations


Φ=NBA
EMF= (delta)Φ/(delta)t
V=IR

The Attempt at a Solution


so i found the area (0.25x0.3) and then divided by two (=0.0375m^2) , then found Φ=80x1.4x0.0375=4.2wb
However , in the marking scheme they multiplayed by the speed instead of area !
upload_2014-12-30_13-34-31.png
 

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So, you calculated ##\Phi##. But for the emf you need ##d\Phi\over dt##. Is the step from one to the other unclear to you ?
 
BvU said:
So, you calculated ##\Phi##. But for the emf you need ##d\Phi\over dt##. Is the step from one to the other unclear to you ?
i know i have to use dΦ/dt , that's why i calculated Φ .. couldn't get how they found 0.7v
 
Area with magnetic field within the loop is xy . x is constant, 0.25 m. At t=0 y = 0.15 m . When the coil is moving, y decreases by 2 m/s
 
BvU said:
Area with magnetic field within the loop is xy . x is constant, 0.25 m. At t=0 y = 0.15 m . When the coil is moving, y decreases by 2 m/s
so its like we make change of "y" over time equals to the speed ? since speed = distance covered / time taken
 
That is exactly what it is !
 

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