Solving Pendulum Question on Physics Quiz: Length 2m, 10 Oscillations in 32 secs

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The discussion revolves around calculating the gravitational acceleration on a moon using the formula g=4π²L/T², given a pendulum length of 2m and a period derived from 10 oscillations in 32 seconds. The initial calculation incorrectly uses a period of 3.125 seconds instead of the correct 3.2 seconds. This mistake leads to an incorrect value for gravity, which does not match any of the provided answer choices. The correct approach confirms that the period should be calculated as T=t/r=32/10=3.2 seconds. Thus, the correct value for gravity can be determined by properly substituting this period into the formula.
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I'm having a problem with just one question on this week's physics quiz-
a pendulum with length 2m on a moon oscillates 10 times in 32 seconds, what is the gravity on this moon?

i know (or thought i knew) how to get the answer to this, with the simple formula g=4pi^2L/T^2

10 oscillations in 32 seconds means a frequency of .32Hz, right? and T=1/f so T=3.125, right?
so when i plug in T as 3.125 and L as 2, i get an answer of 8.08 m/s^2

this is not one of the answer choices, however. my choices are 2.54, 9.86, 7.71, and 3.86
what have i done wrong?
 
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Your approach is correct, Your arithmetic is wrong. The Period would be equal to 3.2
 
10 oscillations in 32 seconds means a frequency of .32Hz, right? and T=1/f so T=3.125, right?
Actually,you are not right.
T=t/r=32/10=3.2 second.
 
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