Solving Piecewise Functions in C_p (0, pi) and C ' _p (0, pi)

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Homework Statement



Which are in C_p (0, pi) and/or in C ' _p (0, pi)?

f(x) = {x if 0 < x < pi/2, pi-x if pi/2 < x < pi
g(x) = {sqrt(x) if 0 < x < pi/3, (pi-x)^2 if pi/3 < x < pi
h(x) = {x if 0 < x < pi/2, ln(pi-x) if pi/2 < x < pi


Homework Equations



(see equations above)

The Attempt at a Solution



I know C_p means "piecewise continuous" but what is C ' _p? How do you do these? I've been racking my brain on this, am completely lost.
 
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If you know what piecewise continuous is, that's good. Which are? I have no clue what C'_p means. Can you look it up and tell us?
 
I looked in my book and lecture notes - they don't say!
 
Then you have perfect justification for not answering the question. Seek clarification. Do you think it might mean differentiable?
 
Or maybe piecewise differentiable
 
That would be my guess.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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